Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 208772 by Jubr last updated on 22/Jun/24

Answered by mr W last updated on 22/Jun/24

Commented by mr W last updated on 22/Jun/24

(r−a)^2 +(r−(a/2))^2 =r^2 4r^2 −12ar+5a^2 =0 a=((2r)/5)=((2×5)/5)=2 area of square =a^2 =2^2 =4

$$\left({r}−{a}\right)^{\mathrm{2}} +\left({r}−\frac{{a}}{\mathrm{2}}\right)^{\mathrm{2}} ={r}^{\mathrm{2}} \\ $$$$\mathrm{4}{r}^{\mathrm{2}} −\mathrm{12}{ar}+\mathrm{5}{a}^{\mathrm{2}} =\mathrm{0} \\ $$$${a}=\frac{\mathrm{2}{r}}{\mathrm{5}}=\frac{\mathrm{2}×\mathrm{5}}{\mathrm{5}}=\mathrm{2} \\ $$$${area}\:{of}\:{square}\:={a}^{\mathrm{2}} =\mathrm{2}^{\mathrm{2}} =\mathrm{4} \\ $$

Commented by Tawa11 last updated on 22/Jun/24

Thanks sir. I really appreciate sir.

$$\mathrm{Thanks}\:\mathrm{sir}. \\ $$$$\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{sir}. \\ $$

Commented by Wuji last updated on 23/Jun/24

sir, what app do you use for the duagrams?

$$\boldsymbol{\mathrm{sir}},\:\boldsymbol{\mathrm{what}}\:\boldsymbol{\mathrm{app}}\:\boldsymbol{\mathrm{do}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{use}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{duagrams}}? \\ $$

Commented by mr W last updated on 23/Jun/24

Photo Editor

$${Photo}\:{Editor} \\ $$

Answered by cherokeesay last updated on 22/Jun/24

Commented by Tawa11 last updated on 22/Jun/24

Thanks sir, I really appreciate sir.

$$\mathrm{Thanks}\:\mathrm{sir},\:\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{sir}. \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com