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Question Number 208581 by Tawa11 last updated on 18/Jun/24

Commented by mr W last updated on 18/Jun/24

Commented by Tawa11 last updated on 18/Jun/24

Thanks sir.

$$\mathrm{Thanks}\:\mathrm{sir}. \\ $$

Answered by A5T last updated on 18/Jun/24

Commented by A5T last updated on 18/Jun/24

2^2 −2×2×5cosθ=+2×3×4cosθ ⇒cosθ=(1/(11)) AB=(√(2^2 +5^2 −2×2×5×(1/(11))))=((√(3289))/(11)) ((abc)/(4R))=(1/2)×2×5×((√(120))/(11))⇒R=((√(3289))/( 2(√(120))))

$$\mathrm{2}^{\mathrm{2}} −\mathrm{2}×\mathrm{2}×\mathrm{5}{cos}\theta=+\mathrm{2}×\mathrm{3}×\mathrm{4}{cos}\theta \\ $$$$\Rightarrow{cos}\theta=\frac{\mathrm{1}}{\mathrm{11}} \\ $$$${AB}=\sqrt{\mathrm{2}^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} −\mathrm{2}×\mathrm{2}×\mathrm{5}×\frac{\mathrm{1}}{\mathrm{11}}}=\frac{\sqrt{\mathrm{3289}}}{\mathrm{11}} \\ $$$$\frac{{abc}}{\mathrm{4}{R}}=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{2}×\mathrm{5}×\frac{\sqrt{\mathrm{120}}}{\mathrm{11}}\Rightarrow{R}=\frac{\sqrt{\mathrm{3289}}}{\:\mathrm{2}\sqrt{\mathrm{120}}} \\ $$

Commented by Tawa11 last updated on 18/Jun/24

Thanks sir

$$\mathrm{Thanks}\:\mathrm{sir} \\ $$

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