Question Number 207774 by Ari last updated on 25/May/24 | ||
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Commented by Rasheed.Sindhi last updated on 26/May/24 | ||
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$$\mathrm{No}\:\mathrm{unique}\:\mathrm{answer}. \\ $$ | ||
Commented by Ari last updated on 26/May/24 | ||
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$${sir}\:{is}\:{not}\:{a}=\mathrm{8}\:{and}\:{b}=\mathrm{3}\:{because}\:{a}>{b}? \\ $$ | ||
Commented by Rasheed.Sindhi last updated on 26/May/24 | ||
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$${Of}\:{course}!\:{But}\:{you}\:{should}\:{explicitly} \\ $$$${mentiom}\:{the}\:{condition}:\:{a}>{b}. \\ $$ | ||
Commented by Ari last updated on 26/May/24 | ||
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$$\boldsymbol{{O}}{K}\:{Sir},{thank}\:{you}! \\ $$ | ||
Answered by Rasheed.Sindhi last updated on 26/May/24 | ||
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$${Assuming}\:{a},{b}\in\mathbb{N} \\ $$$${a}\left({a}+{b}\right)=\mathrm{88}\:;\:{a}<{a}+{b} \\ $$$${a}\left({a}+{b}\right)=\mathrm{1}×\mathrm{88}\Rightarrow{a}=\mathrm{1},{b}=\mathrm{87} \\ $$$${a}\left({a}+{b}\right)=\mathrm{2}×\mathrm{44}\Rightarrow{a}=\mathrm{2},{b}=\mathrm{42} \\ $$$${a}\left({a}+{b}\right)=\mathrm{4}×\mathrm{22}\Rightarrow{a}=\mathrm{4},{b}=\mathrm{18} \\ $$$${a}\left({a}+{b}\right)=\mathrm{8}×\mathrm{11}\Rightarrow{a}=\mathrm{8},{b}=\mathrm{3} \\ $$ | ||