Question Number 207687 by efronzo1 last updated on 23/May/24
Answered by A5T last updated on 23/May/24
Commented by A5T last updated on 23/May/24
![[OAB]=((9(√3))/4); [sector OAC]=[sector OBD]=((3π)/4) ⇒Shaded Area=((9(√3))/4)+((3π)/2)](Q207697.png)
$$\left[{OAB}\right]=\frac{\mathrm{9}\sqrt{\mathrm{3}}}{\mathrm{4}}; \\ $$$$\left[{sector}\:{OAC}\right]=\left[{sector}\:{OBD}\right]=\frac{\mathrm{3}\pi}{\mathrm{4}} \\ $$$$\Rightarrow{Shaded}\:{Area}=\frac{\mathrm{9}\sqrt{\mathrm{3}}}{\mathrm{4}}+\frac{\mathrm{3}\pi}{\mathrm{2}} \\ $$