Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 206614 by cortano21 last updated on 20/Apr/24

Commented by BaliramKumar last updated on 20/Apr/24

Q. 188151

$$\mathrm{Q}.\:\mathrm{188151} \\ $$

Answered by BaliramKumar last updated on 20/Apr/24

2022((2022)/(2023)) = ((2022×2023+2022)/(2023)) = (((2023+1)2022)/(2023))          ⇒ ((2024×2022)/(2023)) = ((2023^2 −1)/(2023))

$$\mathrm{2022}\frac{\mathrm{2022}}{\mathrm{2023}}\:=\:\frac{\mathrm{2022}×\mathrm{2023}+\mathrm{2022}}{\mathrm{2023}}\:=\:\frac{\left(\mathrm{2023}+\mathrm{1}\right)\mathrm{2022}}{\mathrm{2023}}\:\:\:\:\:\:\:\: \\ $$$$\Rightarrow\:\frac{\mathrm{2024}×\mathrm{2022}}{\mathrm{2023}}\:=\:\frac{\mathrm{2023}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2023}} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com