Question Number 205227 by Ari last updated on 13/Mar/24 | ||
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Commented by Ari last updated on 13/Mar/24 | ||
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$${colored}\:{surface}? \\ $$ | ||
Commented by cherokeesay last updated on 13/Mar/24 | ||
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Answered by A5T last updated on 13/Mar/24 | ||
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Commented by A5T last updated on 13/Mar/24 | ||
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$$\left(\mathrm{10}+{x}\right)^{\mathrm{2}} =\mathrm{24}^{\mathrm{2}} +\mathrm{32}^{\mathrm{2}} \Rightarrow{x}=\mathrm{30}\: \\ $$$$\frac{\mathrm{30}}{\mathrm{40}}=\frac{{y}}{\mathrm{24}}\Rightarrow{y}=\mathrm{18}\: \\ $$$${x}^{\mathrm{2}} ={y}^{\mathrm{2}} +{z}^{\mathrm{2}} \Rightarrow{z}=\mathrm{24} \\ $$$$\Rightarrow{Area}=\frac{\left(\mathrm{18}+\mathrm{24}\right)×\mathrm{8}}{\mathrm{2}}=\mathrm{168} \\ $$ | ||