Question Number 204141 by Tawa11 last updated on 06/Feb/24 | ||
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Answered by deleteduser1 last updated on 07/Feb/24 | ||
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$${A}_{\mathrm{3}} \cap{A}_{−\mathrm{3}} =\left(−\infty,−\mathrm{3}\right]=\cap_{{i}=−\mathrm{3}} ^{\mathrm{3}} \\ $$ | ||
Commented by Tawa11 last updated on 07/Feb/24 | ||
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$$\mathrm{I}\:\mathrm{appreciate}\:\mathrm{sir}. \\ $$ | ||