Question Number 199766 by cortano12 last updated on 09/Nov/23 | ||
Answered by mr W last updated on 09/Nov/23 | ||
Commented by mr W last updated on 09/Nov/23 | ||
$${x}=\sqrt{\mathrm{20}^{\mathrm{2}} +\mathrm{21}^{\mathrm{2}} }=\mathrm{29} \\ $$ | ||
Commented by cortano12 last updated on 09/Nov/23 | ||
$$\mathrm{great} \\ $$ | ||