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Question Number 199174 by tri26112004 last updated on 29/Oct/23

Answered by ajfour last updated on 29/Oct/23

If i take ∠ACI =θ  then  ((CI)/(HI))=((sin θ)/(2−sin θ))

$${If}\:{i}\:{take}\:\angle{ACI}\:=\theta\:\:{then} \\ $$$$\frac{{CI}}{{HI}}=\frac{\mathrm{sin}\:\theta}{\mathrm{2}−\mathrm{sin}\:\theta} \\ $$

Commented by tri26112004 last updated on 01/Nov/23

You can use the coordinate

$${You}\:{can}\:{use}\:{the}\:{coordinate}\: \\ $$

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