Question Number 198313 by sonukgindia last updated on 17/Oct/23 | ||
Commented by deleteduser1 last updated on 17/Oct/23 | ||
$${n}^{\mathrm{2}} \equiv\mathrm{34}\left({mod}\:\mathrm{15}\right)?\Rightarrow{n}^{\mathrm{2}} \equiv\mathrm{4}\left({mod}\:\mathrm{15}\right) \\ $$$$\Rightarrow{n}=\mathrm{2},\mathrm{7},\mathrm{8},\mathrm{13}\left({mod}\:\mathrm{15}\right) \\ $$ | ||