Question Number 197371 by Mastermind last updated on 15/Sep/23 | ||
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Answered by Rasheed.Sindhi last updated on 15/Sep/23 | ||
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$${d}:{dog},\:{c}:{cat},\:{r}:{rat} \\ $$$${d}+{r}=\mathrm{20}...\left({i}\right) \\ $$$${c}+{r}=\mathrm{10}...\left({ii}\right) \\ $$$${d}+{c}=\mathrm{24}...\left({iii}\right) \\ $$$$\left({i}\right)+\left({ii}\right)+\left({iii}\right): \\ $$$$\mathrm{2}\left({d}+{c}+{r}\right)=\mathrm{20}+\mathrm{10}+\mathrm{24}=\mathrm{54} \\ $$$${d}+{c}+{r}=\frac{\mathrm{54}}{\mathrm{2}}=\mathrm{27} \\ $$ | ||
Commented by Mastermind last updated on 25/Sep/23 | ||
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$${Thank}\:{you}\:{so}\:{much}\:{BOSS} \\ $$ | ||