Question Number 195896 by AROUNAMoussa last updated on 12/Aug/23 | ||
Answered by HeferH last updated on 13/Aug/23 | ||
Commented by HeferH last updated on 13/Aug/23 | ||
$$\mathrm{180}°−\mathrm{4}{x}\:+\:\mathrm{40}°+\mathrm{2}{x}\:=\:\mathrm{180}° \\ $$$$\:\mathrm{40}°\:−\mathrm{2}{x}\:=\:\mathrm{0} \\ $$$$\:\mathrm{20}°\:=\:{x}\: \\ $$ | ||
Answered by cherokeesay last updated on 13/Aug/23 | ||