Question Number 195702 by Humble last updated on 08/Aug/23 | ||
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Answered by mr W last updated on 08/Aug/23 | ||
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$$\rho_{\mathrm{1}} {gh}_{\mathrm{1}} =\rho_{\mathrm{2}} {gh}_{\mathrm{2}} \\ $$$$\Rightarrow\rho_{\mathrm{2}} =\frac{{h}_{\mathrm{1}} \rho_{\mathrm{1}} }{{h}_{\mathrm{2}} } \\ $$ | ||