Question Number 195208 by Mastermind last updated on 27/Jul/23 | ||
Answered by BaliramKumar last updated on 27/Jul/23 | ||
$$\mathrm{3}\left[\frac{\mathrm{3}\left(\mathrm{3}+\mathrm{1}\right)}{\mathrm{2}}\right]\:=\:\mathrm{18} \\ $$ | ||
Commented by BaliramKumar last updated on 27/Jul/23 | ||
Answered by mr W last updated on 27/Jul/23 | ||
$$\mathrm{3}×{C}_{\mathrm{2}} ^{\mathrm{4}} =\mathrm{3}×\mathrm{6}=\mathrm{18} \\ $$ | ||
Commented by mr W last updated on 27/Jul/23 | ||
Commented by mr W last updated on 27/Jul/23 | ||
$${generally}: \\ $$$${number}\:{of}\:{triangles}\:={m}×{C}_{\mathrm{2}} ^{{n}} =\frac{{mn}\left({n}−\mathrm{1}\right)}{\mathrm{2}} \\ $$ | ||
Answered by York12 last updated on 27/Jul/23 | ||
$$\left(\mathrm{1}+\mathrm{2}+\mathrm{3}\right)×\mathrm{3}=\mathrm{18} \\ $$ | ||
Answered by jaoa_ao1 last updated on 27/Jul/23 | ||
$$\mathrm{zjzjmsms} \\ $$ | ||
Commented by York12 last updated on 27/Jul/23 | ||
$$¿¿ \\ $$ | ||