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Question Number 194818 by sonukgindia last updated on 16/Jul/23

Answered by sniper237 last updated on 16/Jul/23

=^(x=u^2 ) ∫_0 ^1  (√(1−u)) ×(2lnu)×(2udu)  = 4 ∫_0 ^1  u^(2−1) (1−u)^((3/2)−1) lnu du  = 4 ∂_x B_(∣(2;(3/2)))   special Euler funcions

$$\overset{{x}={u}^{\mathrm{2}} } {=}\int_{\mathrm{0}} ^{\mathrm{1}} \:\sqrt{\mathrm{1}−{u}}\:×\left(\mathrm{2}{lnu}\right)×\left(\mathrm{2}{udu}\right) \\ $$$$=\:\mathrm{4}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:{u}^{\mathrm{2}−\mathrm{1}} \left(\mathrm{1}−{u}\right)^{\frac{\mathrm{3}}{\mathrm{2}}−\mathrm{1}} {lnu}\:{du} \\ $$$$=\:\mathrm{4}\:\partial_{{x}} {B}_{\mid\left(\mathrm{2};\frac{\mathrm{3}}{\mathrm{2}}\right)} \\ $$$${special}\:{Euler}\:{funcions}\: \\ $$

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