Question Number 194031 by Mingma last updated on 26/Jun/23 | ||
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Commented by ellen12 last updated on 26/Jun/23 | ||
Impressive | ||
Answered by mr W last updated on 27/Jun/23 | ||
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$${R}={radius}\:{of}\:{circle} \\ $$$$\frac{\mathrm{2}{R}}{{a}}=\sqrt{\mathrm{2}} \\ $$$$\Rightarrow{R}=\frac{{a}}{\:\sqrt{\mathrm{2}}} \\ $$$${area}\:{of}\:{circle}\:=\pi{R}^{\mathrm{2}} =\frac{\pi{a}^{\mathrm{2}} }{\mathrm{2}} \\ $$ | ||
Commented by Mingma last updated on 26/Jun/23 | ||
Perfect | ||
Commented by mr W last updated on 26/Jun/23 | ||
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Commented by mr W last updated on 26/Jun/23 | ||
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$${blue}\:{triangle}\:\sim\:{green}\:{triangle} \\ $$$${in}\:{ratio}\:\mathrm{1}\::\:\sqrt{\mathrm{2}} \\ $$ | ||
Commented by Mingma last updated on 26/Jun/23 | ||
Perfect | ||