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Question Number 193967 by Risandu last updated on 24/Jun/23

Answered by MM42 last updated on 24/Jun/23

lim_(θ→π)   ((4sinθcosθ(cosθ−sin3θ))/((π−θ)(π+θ)))  let    θ=π−u  ⇒lim_(u→0)  ((−4sinu×cosu×(sin3u−cosu))/(u×(2π−u)))   =(2/π) ✓

$${lim}_{\theta\rightarrow\pi} \:\:\frac{\mathrm{4}{sin}\theta{cos}\theta\left({cos}\theta−{sin}\mathrm{3}\theta\right)}{\left(\pi−\theta\right)\left(\pi+\theta\right)} \\ $$$${let}\:\:\:\:\theta=\pi−{u} \\ $$$$\Rightarrow{lim}_{{u}\rightarrow\mathrm{0}} \:\frac{−\mathrm{4}{sinu}×{cosu}×\left({sin}\mathrm{3}{u}−{cosu}\right)}{{u}×\left(\mathrm{2}\pi−{u}\right)} \\ $$$$\:=\frac{\mathrm{2}}{\pi}\:\checkmark \\ $$

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