Question Number 193761 by AZEEZAY last updated on 19/Jun/23 | ||
Answered by Frix last updated on 19/Jun/23 | ||
$$\mathrm{Simply}\:\mathrm{use}\:\mathrm{this}: \\ $$$${c}=\mathrm{log}_{{b}} \:{a}\:\Leftrightarrow\:{a}={b}^{{c}} \\ $$ | ||
Answered by SaRahAli last updated on 19/Jun/23 | ||
$$\mathrm{T}=\mathrm{0}.\mathrm{1585} \\ $$ | ||