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Question Number 193688 by Mingma last updated on 18/Jun/23

Answered by cortano12 last updated on 18/Jun/23

 4(2p+1)^2 −4.(−1).(−2p−31)<0   4p^2 +4p+1−2p−31<0   4p^2 +2p−30<0   2p^2 +p−15<0   (2p −5)(p+3)<0   −3<p<(5/2)   the largest positive integer p is 2

$$\:\mathrm{4}\left(\mathrm{2p}+\mathrm{1}\right)^{\mathrm{2}} −\mathrm{4}.\left(−\mathrm{1}\right).\left(−\mathrm{2p}−\mathrm{31}\right)<\mathrm{0} \\ $$$$\:\mathrm{4p}^{\mathrm{2}} +\mathrm{4p}+\mathrm{1}−\mathrm{2p}−\mathrm{31}<\mathrm{0} \\ $$$$\:\mathrm{4p}^{\mathrm{2}} +\mathrm{2p}−\mathrm{30}<\mathrm{0} \\ $$$$\:\mathrm{2p}^{\mathrm{2}} +\mathrm{p}−\mathrm{15}<\mathrm{0} \\ $$$$\:\left(\mathrm{2p}\:−\mathrm{5}\right)\left(\mathrm{p}+\mathrm{3}\right)<\mathrm{0} \\ $$$$\:−\mathrm{3}<\mathrm{p}<\frac{\mathrm{5}}{\mathrm{2}} \\ $$$$\:\mathrm{the}\:\mathrm{largest}\:\mathrm{positive}\:\mathrm{integer}\:\mathrm{p}\:\mathrm{is}\:\mathrm{2}\: \\ $$

Commented by Mingma last updated on 18/Jun/23

Perfect ��

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