Question Number 193671 by cherokeesay last updated on 17/Jun/23
Answered by mr W last updated on 17/Jun/23
$${R}={radius} \\ $$$${a}={width}\:{of}\:{rectangle} \\ $$$$\mathrm{4}^{\mathrm{2}} −{a}^{\mathrm{2}} ={a}\left(\mathrm{2}{R}−{a}\right) \\ $$$$\Rightarrow{Ra}=\frac{\mathrm{4}^{\mathrm{2}} }{\mathrm{2}} \\ $$$${area}\:{of}\:{rectangle}={Ra}=\frac{\mathrm{4}^{\mathrm{2}} }{\mathrm{2}}=\mathrm{8} \\ $$
Commented by cherokeesay last updated on 18/Jun/23
$${thank}\:{you}. \\ $$
Commented by som(math1967) last updated on 18/Jun/23
$${Welcome}\:{sir}\:{W}\:,\:{after}\:{long}\:{days} \\ $$
Commented by mr W last updated on 18/Jun/23
$${thank}\:{you}\:{sir}! \\ $$
Commented by mnjuly1970 last updated on 18/Jun/23
$$\:\:{Welcome}\:{sir}\:{W}\:... \\ $$