Question Number 192514 by Tomal last updated on 19/May/23
Commented by Skabetix last updated on 19/May/23
$$\frac{\mathrm{2}{log}_{\mathrm{2}} \left(\mathrm{7}\right)}{\mathrm{3}} \\ $$
Commented by Tomal last updated on 20/May/23
$${yes}\:{right} \\ $$
Answered by Frix last updated on 20/May/23
$${p}^{\mathrm{q}} =\mathrm{r}\:\Rightarrow\:{q}=\frac{\mathrm{ln}\:{r}}{\mathrm{ln}\:{p}} \\ $$$${a}×{b}×{c}×{d}×{e}×{f}=\frac{\mathrm{ln}\:\mathrm{4}}{\mathrm{ln}\:\mathrm{3}}×\frac{\mathrm{ln}\:\mathrm{5}}{\mathrm{ln}\:\mathrm{4}}×...×\frac{\mathrm{ln}\:\mathrm{9}}{\mathrm{ln}\:\mathrm{8}}= \\ $$$$=\frac{\mathrm{ln}\:\mathrm{9}}{\mathrm{ln}\:\mathrm{3}}=\frac{\mathrm{2ln}\:\mathrm{3}}{\mathrm{ln}\:\mathrm{3}}=\mathrm{2} \\ $$
Commented by Skabetix last updated on 19/May/23
$${there}\:{is}\:{no}\:``{e}``\:{in}\:{the}\:{question}\:{sir} \\ $$
Commented by Frix last updated on 19/May/23
$$\mathrm{I}\:\mathrm{think}\:\mathrm{it}'\mathrm{s}\:\mathrm{a}\:\mathrm{typo}\:\mathrm{but}\:\mathrm{else}\:\mathrm{you}'\mathrm{re}\:\mathrm{right}. \\ $$
Commented by Tomal last updated on 20/May/23
$${yes} \\ $$