Previous in Relation and Functions Next in Relation and Functions | ||
Question Number 192181 by momdli last updated on 10/May/23 | ||
![]() | ||
Answered by deleteduser1 last updated on 10/May/23 | ||
![]() | ||
$$\mathrm{2}{f}\left({x}\right)+{f}\left(\frac{\mathrm{1}}{\mathrm{2}}\right)=\frac{{x}}{\mathrm{2}}\Rightarrow{f}\left(\frac{\mathrm{1}}{\mathrm{2}}\right)=\frac{\mathrm{1}}{\mathrm{12}} \\ $$$$\Rightarrow{f}\left({x}\right)=\frac{\mathrm{6}{x}−\mathrm{1}}{\mathrm{24}}\Rightarrow{f}\left(\mathrm{3}\right)=\frac{\mathrm{17}}{\mathrm{24}} \\ $$ | ||