Question Number 190819 by Rupesh123 last updated on 12/Apr/23
Answered by HeferH last updated on 13/Apr/23
Commented by HeferH last updated on 13/Apr/23
$$\mathrm{A}+\mathrm{B}\:=\:\mathrm{2A}\:−\mathrm{2B} \\ $$$$\mathrm{3B}\:=\:\mathrm{A} \\ $$$$\frac{\mathrm{PB}}{\mathrm{PA}}\:=\:\frac{\mathrm{4B}}{\mathrm{2B}}\:=\:\frac{\mathrm{2}}{\mathrm{1}} \\ $$$$\therefore\:\:\frac{\mathrm{AC}}{\mathrm{AP}}\:=\:\frac{\mathrm{3}}{\mathrm{1}}\:=\:\mathrm{3} \\ $$
Commented by Rupesh123 last updated on 14/Apr/23
Excellent, sir!