Question Number 190809 by safojontoshtemirov last updated on 12/Apr/23 | ||
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Commented by Frix last updated on 12/Apr/23 | ||
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$$\mathrm{Use}\:\mathrm{2}\:\mathrm{steps}: \\ $$$$\mathrm{1}.\:{t}={x}+\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\mathrm{2}.\:{u}=\mathrm{2}{t}+\sqrt{\mathrm{4}{t}^{\mathrm{2}} −\mathrm{1}} \\ $$ | ||
Commented by safojontoshtemirov last updated on 12/Apr/23 | ||
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$${thenk}\:{you} \\ $$ | ||