Question Number 189023 by Mingma last updated on 10/Mar/23 | ||
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Commented by amin96 last updated on 10/Mar/23 | ||
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$$ \\ $$ | ||
Commented by amin96 last updated on 11/Mar/23 | ||
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$$\boldsymbol{\mathrm{r}}\sqrt{\mathrm{2}}=\left(\mathrm{1}−\boldsymbol{\mathrm{r}}\right)\:\:\:\boldsymbol{\mathrm{r}}+\boldsymbol{\mathrm{r}}\sqrt{\mathrm{2}}=\mathrm{1}\:\:\:\:\boldsymbol{\mathrm{r}}=\frac{\mathrm{1}}{\mathrm{1}+\sqrt{\mathrm{2}}} \\ $$ | ||
Commented by amin96 last updated on 11/Mar/23 | ||
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$$\left.\boldsymbol{\mathrm{O}}\left.\boldsymbol{\mathrm{h}}\:\boldsymbol{\mathrm{yeah}}\right)\right)\: \\ $$ | ||