Question Number 188635 by normans last updated on 04/Mar/23
Answered by nikif99 last updated on 05/Mar/23
$${Two}\:{solutions}\:{found}: \\ $$$${ABCDE}=\mathrm{57674}\:{or}\:\mathrm{77456} \\ $$$${so}\:{A}+{C}−{E}=\mathrm{7}\:{or}\:\mathrm{5} \\ $$
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Question Number 188635 by normans last updated on 04/Mar/23 | ||
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Answered by nikif99 last updated on 05/Mar/23 | ||
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$${Two}\:{solutions}\:{found}: \\ $$$${ABCDE}=\mathrm{57674}\:{or}\:\mathrm{77456} \\ $$$${so}\:{A}+{C}−{E}=\mathrm{7}\:{or}\:\mathrm{5} \\ $$ | ||