Question Number 188615 by normans last updated on 03/Mar/23 | ||
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Answered by HeferH last updated on 03/Mar/23 | ||
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$$\mathrm{37}°? \\ $$ | ||
Commented by HeferH last updated on 04/Mar/23 | ||
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Commented by HeferH last updated on 04/Mar/23 | ||
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$$\mathrm{2}{x}−\mathrm{58}°\:=\:\mathrm{90}°−\mathrm{2}{x} \\ $$$$\:{x}\:=\:\frac{\mathrm{148}°}{\mathrm{4}}\:=\:\mathrm{37}° \\ $$ | ||