Question Number 188520 by Rupesh123 last updated on 02/Mar/23
Answered by HeferH last updated on 02/Mar/23
Commented by HeferH last updated on 02/Mar/23
$${B}+{R}=\:\left(\frac{{r}}{\:\sqrt{\mathrm{2}}}\right)^{\mathrm{2}} \\ $$$$\:\frac{{r}}{\:\sqrt{\mathrm{2}}}\:=\:\mathrm{13}\:\Rightarrow\:{r}\:=\:\mathrm{13}\sqrt{\mathrm{2}} \\ $$$$\:{B}+{R}\:=\:\frac{{r}^{\mathrm{2}} }{\mathrm{2}}\:=\:\mathrm{169}{u}^{\mathrm{2}} \\ $$
Commented by Rupesh123 last updated on 02/Mar/23
Excellent