Question Number 187998 by Mingma last updated on 24/Feb/23 | ||
Answered by mahdipoor last updated on 24/Feb/23 | ||
$$=\frac{\left(\mathrm{16}−\mathrm{2}\right)\left(\mathrm{16}+\mathrm{2}\right)}{\mathrm{18}×\mathrm{13}}×\frac{\left(\mathrm{16}−\mathrm{3}\right)\left(\mathrm{16}+\mathrm{3}\right)}{\mathrm{19}×\mathrm{12}}×...×\frac{\left(\mathrm{16}−\mathrm{8}\right)\left(\mathrm{16}+\mathrm{8}\right)}{\mathrm{24}×\mathrm{7}} \\ $$$$=\frac{\mathrm{14}}{\mathrm{13}}×\frac{\mathrm{13}}{\mathrm{12}}×...×\frac{\mathrm{8}}{\mathrm{7}}=\frac{\mathrm{14}}{\mathrm{7}}=\mathrm{2} \\ $$ | ||
Commented by Mingma last updated on 24/Feb/23 | ||
Very true, sir! | ||