Question Number 187377 by Rupesh123 last updated on 16/Feb/23 | ||
Commented by Rupesh123 last updated on 16/Feb/23 | ||
<theta = ? | ||
Answered by horsebrand11 last updated on 16/Feb/23 | ||
$$\Rightarrow\alpha=\mathrm{90}°−\beta \\ $$$$\Rightarrow\mathrm{tan}\:\alpha=\mathrm{2}\:;\:\mathrm{tan}\:\beta=\frac{{x}}{\mathrm{5}}\: \\ $$$$\Rightarrow\mathrm{tan}\:\alpha.\mathrm{tan}\:\beta=\mathrm{1} \\ $$$$\Rightarrow{x}=\frac{\mathrm{5}}{\mathrm{2}}\:{and}\:\mathrm{tan}\:\theta=\frac{\mathrm{10}}{\mathrm{10}−\frac{\mathrm{5}}{\mathrm{2}}}=\frac{\mathrm{4}}{\mathrm{3}}\:\: \\ $$ | ||