Question Number 186069 by TUN last updated on 31/Jan/23 | ||
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Answered by HeferH last updated on 31/Jan/23 | ||
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$$\alpha=\mathrm{10}° \\ $$ | ||
Commented by HeferH last updated on 31/Jan/23 | ||
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Commented by HeferH last updated on 31/Jan/23 | ||
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$$\mathrm{2}\left(\mathrm{120}°\:−\:\mathrm{4}\alpha\right)\:+\:\mathrm{2}\alpha\:=\:\mathrm{180}° \\ $$$$\mathrm{240}°\:−\:\mathrm{6}\alpha=\mathrm{180}° \\ $$$$\:\alpha\:=\:\frac{\mathrm{60}°}{\mathrm{6}}\:=\:\mathrm{10}° \\ $$ | ||