Question Number 185673 by Mingma last updated on 25/Jan/23 | ||
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Answered by Frix last updated on 25/Jan/23 | ||
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$$\mathrm{Due}\:\mathrm{to}\:\mathrm{symmetry}\:{x}={y}={z}=\frac{\mathrm{1}}{\mathrm{3}}\:\Rightarrow\:\mathrm{maximum} \\ $$$$\mathrm{value}\:\mathrm{is}\:\frac{\mathrm{1}}{\mathrm{27}} \\ $$ | ||