Question Number 183945 by AROUNAMoussa last updated on 31/Dec/22 | ||
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Answered by HeferH last updated on 31/Dec/22 | ||
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Commented by HeferH last updated on 31/Dec/22 | ||
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$$\mathrm{16}\:=\:\mathrm{3}\left(\mathrm{2}{r}\:−\:\mathrm{3}\right) \\ $$$$\:\mathrm{16}\:=\:\mathrm{6}{r}\:−\:\mathrm{9} \\ $$$$\:{r}\:=\:\frac{\mathrm{25}}{\mathrm{6}}\: \\ $$ | ||
Answered by Acem last updated on 31/Dec/22 | ||
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