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Question Number 183803 by Ar Brandon last updated on 30/Dec/22

Answered by mr W last updated on 30/Dec/22

Commented by mr W last updated on 30/Dec/22

ΔAEF≡ΔAEF ′ x=180−70−45=65°

$$\Delta{AEF}\equiv\Delta{AEF}\:' \\ $$$${x}=\mathrm{180}−\mathrm{70}−\mathrm{45}=\mathrm{65}° \\ $$

Commented by Ar Brandon last updated on 30/Dec/22

Thank you Sir

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