Question Number 183734 by AROUNAMoussa last updated on 29/Dec/22 | ||
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Answered by HeferH last updated on 29/Dec/22 | ||
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Commented by HeferH last updated on 29/Dec/22 | ||
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$$\bigtriangleup{ABD}\:\sim\:\bigtriangleup{EBC}\:\Rightarrow \\ $$$$\:\frac{{AB}}{{EB}}\:=\:\frac{{BD}}{{BC}}\: \\ $$$$\:{AB}\centerdot{BC}\:=\:{EB}\centerdot{BD}\: \\ $$ | ||