Question Number 183409 by aurpeyz last updated on 25/Dec/22 | ||
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Commented by Yhusuph last updated on 25/Dec/22 | ||
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$${F}_{{x}} ={F}\bullet{Cos}\mathrm{30}° \\ $$ | ||
Commented by mr W last updated on 25/Dec/22 | ||
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$${F}_{{x}} ={F}\:\mathrm{cos}\:\mathrm{30}°={F}\:\mathrm{sin}\:\mathrm{60}° \\ $$$$\Rightarrow{answer}\:\left(\mathrm{4}\right) \\ $$ | ||
Commented by aurpeyz last updated on 26/Dec/22 | ||
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$${thanks} \\ $$ | ||