Question Number 183389 by Acem last updated on 25/Dec/22 | ||
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Answered by HeferH last updated on 25/Dec/22 | ||
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$$\mathrm{65}°\:=\:{x} \\ $$$$\left.{Merry}\:{xmas}\:{btw}\::\right) \\ $$ | ||
Commented by Acem last updated on 26/Dec/22 | ||
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$$\:\left(:\:\:{Merry}\:{xmas}\:{you}\:{too},\:{hope}\:{you}\:{always}\:{doing}\right. \\ $$$$\:{good}\:{and}\:{smile}!\:{Thanks}\:{Sir}! \\ $$ | ||
Answered by mr W last updated on 25/Dec/22 | ||
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Commented by mr W last updated on 25/Dec/22 | ||
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$${x}=\mathrm{90}−\mathrm{25}=\mathrm{65}° \\ $$ | ||
Commented by Acem last updated on 26/Dec/22 | ||
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$${Thanks}\:{Sir}! \\ $$ | ||