Question Number 172603 by Mikenice last updated on 29/Jun/22 | ||
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Answered by mr W last updated on 29/Jun/22 | ||
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Commented by mr W last updated on 29/Jun/22 | ||
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$$\mathrm{tan}\:\theta=\frac{\mathrm{100}}{\mathrm{30}}=\frac{\mathrm{10}}{\mathrm{3}} \\ $$$$\theta=\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{10}}{\mathrm{3}}\approx\mathrm{73}.\mathrm{3}° \\ $$ | ||
Commented by Tawa11 last updated on 30/Jun/22 | ||
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$$\mathrm{Great}\:\mathrm{sir} \\ $$ | ||