Question Number 172532 by Mikenice last updated on 28/Jun/22 | ||
Answered by MJS_new last updated on 28/Jun/22 | ||
$${x}_{\mathrm{1}} \approx−\mathrm{4}.\mathrm{24290} \\ $$$${x}_{\mathrm{2}} \approx.\mathrm{0593074} \\ $$$${x}_{\mathrm{3}} =\mathrm{3} \\ $$ | ||
Commented by Mikenice last updated on 28/Jun/22 | ||
$${please}\:{show}\:{the}\:{workings} \\ $$ | ||
Answered by Rasheed.Sindhi last updated on 28/Jun/22 | ||
$${x}^{\mathrm{3}} +\mathrm{3}^{{x}} =\mathrm{18}{x} \\ $$$${Solving}\:{for}\:\boldsymbol{{whole}}\:{x} \\ $$$$\mathrm{3}\mid\mathrm{18}{x}\Rightarrow\mathrm{3}\mid\left({x}^{\mathrm{3}} +\mathrm{3}^{{x}} \right)\Rightarrow\mathrm{3}\mid{x}......\left({i}\right) \\ $$$${x}\mid\mathrm{18}{x}\Rightarrow{x}\mid\left({x}^{\mathrm{3}} +\mathrm{3}^{{x}} \right)\Rightarrow{x}\mid\mathrm{3}.....\left({ii}\right) \\ $$$${From}\:\left({i}\right)\:\&\:\left({ii}\right):\:\:{x}=\mathrm{3} \\ $$ | ||