Question Number 172225 by mnjuly1970 last updated on 24/Jun/22 | ||
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Answered by infinityaction last updated on 24/Jun/22 | ||
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Commented by mnjuly1970 last updated on 24/Jun/22 | ||
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$${thanks}\:{alot}\:{sir} \\ $$ | ||
Commented by infinityaction last updated on 24/Jun/22 | ||
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$$\:\:{A}\:=\:\frac{\pi\left(\sqrt{\mathrm{20}}\right)^{\mathrm{2}} }{\mathrm{4}}\:\:=\:\:\mathrm{5}\pi \\ $$ | ||