Question Number 171014 by Beginner last updated on 06/Jun/22 | ||
Answered by greougoury555 last updated on 06/Jun/22 | ||
$$\:=\:\int\left(\frac{\mathrm{1}}{\mathrm{7}}{e}^{\mathrm{7}{x}} +\mathrm{3}{e}^{−\mathrm{2}{x}} \right){dx} \\ $$$$=\frac{\mathrm{1}}{\mathrm{49}}{e}^{\mathrm{7}{x}} −\frac{\mathrm{3}}{\mathrm{2}}{e}^{−\mathrm{2}{x}} +{c}\: \\ $$ | ||