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Question Number 167889 by mathlove last updated on 28/Mar/22

Answered by MJS_new last updated on 28/Mar/22

y=x^y   ⇒ (dx/dy)=((x^y y)/(x(1−x^y ln x)))

$${y}={x}^{{y}} \\ $$$$\Rightarrow\:\frac{{dx}}{{dy}}=\frac{{x}^{{y}} {y}}{{x}\left(\mathrm{1}−{x}^{{y}} \mathrm{ln}\:{x}\right)} \\ $$

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