Question Number 167713 by infinityaction last updated on 23/Mar/22
Answered by Nimatullah last updated on 23/Mar/22
![∫_0 ^∞ (1/(x+1))dx=ln[x+1]_0 ^∞ =∞](Q167715.png)
$$\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{1}}{{x}+\mathrm{1}}{dx}=\mathrm{ln}\left[{x}+\mathrm{1}\right]_{\mathrm{0}} ^{\infty} =\infty \\ $$