Question Number 166818 by ajfour last updated on 28/Feb/22 | ||
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Commented by som(math1967) last updated on 28/Feb/22 | ||
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$${R}=\frac{\mathrm{10}}{\mathrm{3}},\:{r}=\frac{\mathrm{15}}{\mathrm{8}}\:\:{sir}? \\ $$ | ||
Commented by ajfour last updated on 28/Feb/22 | ||
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$${Thank}\:{you}\:{sirs}. \\ $$ | ||
Commented by Tawa11 last updated on 01/Mar/22 | ||
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$$\mathrm{Great}\:\mathrm{sir} \\ $$ | ||
Answered by mr W last updated on 28/Feb/22 | ||
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$$\frac{\left(\frac{\mathrm{3}}{\mathrm{2}}\right)}{{r}}=\frac{\mathrm{4}}{\mathrm{5}}\:\Rightarrow{r}=\frac{\mathrm{15}}{\mathrm{8}} \\ $$$$\frac{\left(\frac{\mathrm{4}}{\mathrm{2}}\right)}{{R}}=\frac{\mathrm{3}}{\mathrm{5}}\:\Rightarrow{R}=\frac{\mathrm{10}}{\mathrm{3}} \\ $$ | ||
Commented by Tawa11 last updated on 01/Mar/22 | ||
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$$\mathrm{Great}\:\mathrm{sir} \\ $$ | ||