Question Number 166774 by BagusSetyoWibowo last updated on 27/Feb/22
Commented by cortano1 last updated on 27/Feb/22
$$\Rightarrow\mathrm{x}=\sqrt{\mathrm{25}−\mathrm{24}.\frac{\mathrm{1}}{\mathrm{2}}}=\sqrt{\mathrm{13}}\:\mathrm{cm} \\ $$$$\Rightarrow\mathrm{Area}=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{12}×\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{3}}=\mathrm{3}\sqrt{\mathrm{3}}\:\mathrm{cm}^{\mathrm{2}} \\ $$