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Question Number 164996 by Mathematification last updated on 24/Jan/22
Answered by mr W last updated on 25/Jan/22
$${AB}={x}_{\mathrm{1}} +{x}_{\mathrm{2}} \\ $$$${AB}=\sqrt{\left(\mathrm{3}+\mathrm{2}\right)^{\mathrm{2}} −\left(\mathrm{3}−\mathrm{2}\right)^{\mathrm{2}} }+\sqrt{\left(\mathrm{2}+\mathrm{1}.\mathrm{5}\right)^{\mathrm{2}} −\left(\mathrm{4}.\mathrm{5}−\mathrm{2}\right)^{\mathrm{2}} } \\ $$$${AB}=\sqrt{\mathrm{24}}+\sqrt{\mathrm{6}}=\mathrm{3}\sqrt{\mathrm{6}} \\ $$
Commented by mr W last updated on 25/Jan/22
Commented by Tawa11 last updated on 25/Jan/22
$$\mathrm{Great}\:\mathrm{sir} \\ $$