Question Number 164315 by ajfour last updated on 16/Jan/22 | ||
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Commented by ajfour last updated on 16/Jan/22 | ||
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$${If}\:{the}\:{blue}\:{area}\:{is}\:\:\:{c}\:\:\:{units},\:{find}\:{p}. \\ $$ | ||
Commented by cortano1 last updated on 16/Jan/22 | ||
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$$\:\left(\mathrm{1}\right)\:{c}\:=\:\frac{\mathrm{1}}{\mathrm{2}}×\left({p}^{\mathrm{2}} −\mathrm{2}\right)\left(\mathrm{2}\sqrt{{p}^{\mathrm{2}} −\mathrm{1}}\right) \\ $$$$\:\:{c}\:=\:\left({p}^{\mathrm{2}} −\mathrm{1}−\mathrm{1}\right)\sqrt{{p}^{\mathrm{2}} −\mathrm{1}}\:;\:\sqrt{{p}^{\mathrm{2}} −\mathrm{1}}\:=\:{y} \\ $$$$\:\:{c}=\left({y}^{\mathrm{2}} −\mathrm{1}\right){y}\: \\ $$$$\:\:{c}=\:{y}^{\mathrm{3}} −{y}\: \\ $$$$\:\:{y}^{\mathrm{3}} −{y}−{c}\:=\:\mathrm{0}\: \\ $$$$\:\: \\ $$$$\: \\ $$ | ||
Commented by ajfour last updated on 16/Jan/22 | ||
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$${Thanks}\:{sir}. \\ $$ | ||