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Question Number 159597 by mathlove last updated on 19/Nov/21
Answered by mr W last updated on 19/Nov/21
(sin2014xsin(2014x)2014)′=2014sin2013xcosxsin(2014x)+sin2014x×2014cos(2014x)2014=sin2013x(cosxsin(2014x)+sinxcos(2014x))=sin2013xsin(2014x+x)=sin2013xsin(2015x)⇒∫sin2013xsin(2015x)dx=sin2014xsin(2014x)2014+C
Commented by mathlove last updated on 20/Nov/21
thenksmaster
Commented by infinityaction last updated on 25/Apr/22
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