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Question Number 159597 by mathlove last updated on 19/Nov/21

Answered by mr W last updated on 19/Nov/21

(((sin^(2014)  x sin (2014x))/(2014)))′  =((2014 sin^(2013)  x cos x sin (2014x)+sin^(2014) x×2014 cos (2014x))/(2014))  =sin^(2013)  x(cos x sin (2014x)+sin x cos (2014x))  =sin^(2013)  x sin (2014x+x)  =sin^(2013)  x sin (2015x)  ⇒∫sin^(2013)  x sin (2015x)dx=((sin^(2014)  x sin (2014x))/(2014))+C

(sin2014xsin(2014x)2014)=2014sin2013xcosxsin(2014x)+sin2014x×2014cos(2014x)2014=sin2013x(cosxsin(2014x)+sinxcos(2014x))=sin2013xsin(2014x+x)=sin2013xsin(2015x)sin2013xsin(2015x)dx=sin2014xsin(2014x)2014+C

Commented by mathlove last updated on 20/Nov/21

thenks master

thenksmaster

Commented by infinityaction last updated on 25/Apr/22

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