Question Number 159355 by mnjuly1970 last updated on 16/Nov/21 | ||
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Answered by mr W last updated on 16/Nov/21 | ||
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$${radius}\:{of}\:{small}\:{circle}\:{r}=\frac{{b}}{\mathrm{2}} \\ $$$$\frac{{b}}{\mathrm{2}}×\frac{{b}}{\mathrm{2}}=\left({a}−\frac{{b}}{\mathrm{2}}\right)\left({a}+\frac{{b}}{\mathrm{2}}\right) \\ $$$$\frac{{b}^{\mathrm{2}} }{\mathrm{4}}={a}^{\mathrm{2}} −\frac{{b}^{\mathrm{2}} }{\mathrm{4}} \\ $$$$\frac{{b}^{\mathrm{2}} }{\mathrm{2}}={a}^{\mathrm{2}} \\ $$$$\Rightarrow\frac{{b}}{{a}}=\sqrt{\mathrm{2}} \\ $$ | ||
Commented by mr W last updated on 16/Nov/21 | ||
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Commented by Tawa11 last updated on 16/Nov/21 | ||
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$$\mathrm{Great}\:\mathrm{sir} \\ $$ | ||
Commented by mnjuly1970 last updated on 16/Nov/21 | ||
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$$\:\:{god}\:{keep}\:{you}\:{master}\:{W} \\ $$ | ||