Question Number 152848 by 0731619 last updated on 02/Sep/21 | ||
Commented by hknkrc46 last updated on 02/Sep/21 | ||
$$\boldsymbol{{Wrong}}\:!!! \\ $$$$\sqrt{\mathrm{12}}\:+\:\cancel{\sqrt{\mathrm{18}}}\:\rightarrow\:\sqrt{\mathrm{12}}\:+\:\sqrt{\mathrm{16}} \\ $$ | ||
Commented by hknkrc46 last updated on 02/Sep/21 | ||
Commented by mathdanisur last updated on 02/Sep/21 | ||
$$\mathrm{Nice}\:\mathrm{brother},\:\mathrm{how}\:\mathrm{we}\:\mathrm{put}\:\mathrm{the}\:\mathrm{shape}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{feathers}\:\mathrm{please} \\ $$ | ||
Commented by john_santu last updated on 02/Sep/21 | ||
$$\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{4}}+\sqrt{\mathrm{8}}}\:+\frac{\mathrm{1}}{\:\sqrt{\mathrm{8}}+\sqrt{\mathrm{12}}}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{12}}+\sqrt{\mathrm{16}}}+...+\frac{\mathrm{1}}{\:\sqrt{\mathrm{396}}+\sqrt{\mathrm{400}}}\:=\:{T} \\ $$$${T}=\:\frac{\sqrt{\mathrm{8}}−\sqrt{\mathrm{4}}}{\mathrm{4}}+\frac{\sqrt{\mathrm{12}}−\sqrt{\mathrm{8}}}{\mathrm{4}}+\frac{\sqrt{\mathrm{16}}−\sqrt{\mathrm{12}}}{\mathrm{4}}+...+\frac{\sqrt{\mathrm{400}}−\sqrt{\mathrm{396}}}{\mathrm{4}} \\ $$$${T}=\frac{\mathrm{1}}{\mathrm{4}}\left(\sqrt{\mathrm{400}}−\sqrt{\mathrm{4}}\right)=\frac{\mathrm{20}−\mathrm{2}}{\mathrm{4}}=\mathrm{4}.\mathrm{5} \\ $$$$ \\ $$ | ||
Commented by Tawa11 last updated on 02/Sep/21 | ||
$$\mathrm{Nice} \\ $$ | ||